|
Denote the matrix c. We
first find its eigenvalues. These are values
such that
 |
[2.68] |
for some non-zero vector v. This is possible
only if the determinant of
is zero, a condition that yields the equation
|
2
– 5
+ 4 = 0 |
[s1] |
Solutions are
= 1 and
= 4. Substituting these into [2.68] and solving, we obtain corresponding
eigenvectors
|
and
 |
[s2] |
|