Use Newton’s method with seed value = 0 to solve the equation:

[2.164]

Newton's method employs the recursive formula

[2.142]

For this exercise,

	[s1]
	[s2]

Starting with seed value = 0, we apply [2.142] recursively. Results are indicated below.

k		f()
1 0.00000 1.00000 2 -1.00000 -2.63212 3 -0.58666 -0.47631 4 -0.46980 -0.03702 5 -0.45905 -0.00031 6 -0.45896 0.00000 7 -0.45896 0.00000